Android调用默认浏览器打开指定Url的方法实例

2019-10-24 20:43:20

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业务员有需求要将一个wap站在手机上以App的形式打开,还不要嵌套WebView,只能以浏览器打开.查了点资料,就有了下面这代码

复制代码代码如下:

package com.gzz.whyinzi;

import android.net.Uri;
import android.os.Bundle;
import android.app.Activity;
import android.content.Intent;
import android.util.Log;
import android.view.Menu;
import android.view.View;

public class MainActivity extends Activity {
    private static final String TAG = "ActivityDemo";

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);


        Intent intent = new Intent();
        intent.setAction("android.intent.action.VIEW");
        Uri content_url = Uri.parse(http://www.vevb.com);
        intent.setData(content_url);
        startActivity(intent);


    }

        @Override
        protected void onResume() {
            super.onResume();
            Intent intent = new Intent();
            intent.setAction("android.intent.action.VIEW");
            Uri content_url = Uri.parse("http://play.vevb.com");
            intent.setData(content_url);
            startActivity(intent);
            Log.e(TAG, "start onResume~~~");
        }

        @Override
        protected void onStop() {
            super.onStop();
            this.finish();
            Log.e(TAG, "start onStop~~~");
        }
}