前言
Django附带的认证对于大多数常见情况来说已经足够了,但是如何在 Django 中使用自定义的数据表进行用户认证,有一种较为笨蛋的办法就是自定义好数据表后,使用OnetoOne来跟 Django 的表进行关联,类似于这样:
from django.contrib.auth.models import Userclass UserProfile(models.Model): """ 用户账号表 """ user = models.OneToOneField(User) name = models.CharField(max_length=32) def __str__(self): return self.name class Meta: verbose_name_plural = verbose_name = "用户账号" ordering = ['id']
这样做虽然可以简单、快速的实现,但是有一个问题就是我们在自己的表中创建一个用户就必须再跟 admin 中的一个用户进行关联,这简直是不可以忍受的。
admin代替默认User model
写我们自定义的 models 类来创建用户数据表来代替默认的User model,而不与django admin的进行关联,相关的官方文档在这里
👾戳我
from django.db import modelsfrom django.contrib.auth.models import Userfrom django.contrib.auth.models import ( BaseUserManager, AbstractBaseUser)class UserProfileManager(BaseUserManager): def create_user(self, email, name, password=None): """ 用户创建,需要提供 email、name、password """ if not email: raise ValueError('Users must have an email address') user = self.model( email=self.normalize_email(email), name=name, ) user.set_password(password) user.save(using=self._db) return user def create_superuser(self, email, name, password): """ 超级用户创建,需要提供 email、name、password """ user = self.create_user( email, password=password, name=name, ) user.is_admin = True user.is_active = True user.save(using=self._db) return userclass UserProfile(AbstractBaseUser): # 在此处可以配置更多的自定义字段 email = models.EmailField( verbose_name='email address', max_length=255, unique=True, ) name = models.CharField(max_length=32, verbose_name="用户名称") phone = models.IntegerField("电话") is_active = models.BooleanField(default=True) is_admin = models.BooleanField(default=False) objects = UserProfileManager() USERNAME_FIELD = 'email' # 将email 作为登入用户名 REQUIRED_FIELDS = ['name', 'phone'] def __str__(self): return self.email def get_full_name(self): # The user is identified by their email address return self.email def get_short_name(self): # The user is identified by their email address return self.email def has_perm(self, perm, obj=None): "Does the user have a specific permission?" # Simplest possible answer: Yes, always return True def has_module_perms(self, app_label): "Does the user have permissions to view the app `app_label`?" # Simplest possible answer: Yes, always return True @property def is_staff(self): "Is the user a member of staff?" # Simplest possible answer: All admins are staff return self.is_admin
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