PYTHON基础-时间日期处理小结

步骤:

1. 掌握几种对象及其关系
2. 了解每类对象的基本操作方法
3. 通过转化关系转化

涉及对象

1. datetime

>>> import datetime>>> now = datetime.datetime.now()>>> nowdatetime.datetime(2018, 1, 12, 23, 9, 12, 946118)>>> type(now)<type 'datetime.datetime'>

2. timestamp

>>> import time>>> time.time()1421075455.568243

3. time tuple

>>> import time>>> time.localtime()time.struct_time(tm_year=2015, tm_mon=1, tm_mday=12, tm_hour=23, tm_min=10, tm_sec=30, tm_wday=0, tm_yday=12, tm_isdst=0)

4. string

>>> import datetime>>> datetime.datetime.now().strftime("%Y-%m-%d %H:%M:%S")'2015-01-12 23:13:08'

5. date

>>> import datetime>>> datetime.datetime.now().date()datetime.date(2015, 1, 12)

datetime基本操作

1. 获取当前datetime

>>> import datetime>>> datetime.datetime.now()datetime.datetime(2015, 1, 12, 23, 26, 24, 475680)

2. 获取当天date

>>> datetime.date.today()datetime.date(2015, 1, 12)

3. 获取明天/前N天

明天

>>> datetime.date.today() + datetime.timedelta(days=1)datetime.date(2015, 1, 13)

三天前

>>> datetime.datetime.now()datetime.datetime(2015, 1, 12, 23, 38, 55, 492226)>>> datetime.datetime.now() - datetime.timedelta(days=3)datetime.datetime(2015, 1, 9, 23, 38, 57, 59363)

4. 获取当天开始和结束时间(00:00:00 23:59:59)

>>> datetime.datetime.combine(datetime.date.today(), datetime.time.min)datetime.datetime(2015, 1, 12, 0, 0)>>> datetime.datetime.combine(datetime.date.today(), datetime.time.max)datetime.datetime(2015, 1, 12, 23, 59, 59, 999999)

5. 获取两个datetime的时间差

>>> (datetime.datetime(2015,1,13,12,0,0) - datetime.datetime.now()).total_seconds()44747.768075

6. 获取本周/本月/上月最后一天

本周

>>> today = datetime.date.today()>>> todaydatetime.date(2015, 1, 12)>>> sunday = today + datetime.timedelta(6 - today.weekday())>>> sundaydatetime.date(2015, 1, 18)

本月

>>> import calendar>>> today = datetime.date.today()>>> _, last_day_num = calendar.monthrange(today.year, today.month)>>> last_day = datetime.date(today.year, today.month, last_day_num)>>> last_daydatetime.date(2015, 1, 31)

获取上个月的最后一天(可能跨年)

>>> import datetime>>> today = datetime.date.today()>>> first = datetime.date(day=1, month=today.month, year=today.year)>>> lastMonth = first - datetime.timedelta(days=1)