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详解Android获取设备唯一ID的几种方式

2019-10-22 18:35:27
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先来看看几种比较单一的方式:

IMEI

方式:TelephonyManager.getDeviceId():

问题

  1. 范围:只能支持拥有通话功能的设备,对于平板不可以。
  2. 持久性:返厂,数据擦除的时候不彻底,保留了原来的标识。
  3. 权限:需要权限:Android.permission.READ_PHONE_STATE
  4. bug: 有些厂家的实现有bug,返回一些不可用的数据

 Mac地址

ACCESS_WIFI_STATE权限

有些设备没有WiFi,或者蓝牙,就不可以,如果WiFi没有打开,硬件也不会返回Mac地址,不建议使用

ANDROID_ID
2.2(Froyo,8)版本系统会不可信,来自主要生产厂商的主流手机,至少有一个普遍发现的bug,这些有问题的手机相同的ANDROID_ID: 9774d56d682e549c

但是如果返厂的手机,或者被root的手机,可能会变

Serial Number

从Android 2.3 (“Gingerbread”)开始可用,可以通过android.os.Build.SERIAL获取,对于没有通话功能的设备,它会返回一个唯一的device ID,

以下几个是stackoverflow上评论较多的几个,没贴完,还有其他,综合的,用到以上的部分方式:

地址:http://stackoverflow.com/questions/2785485/is-there-a-unique-android-device-id

有兴趣的朋友可以再仔细看看

支持率比较高的(支持票数157):androidID --> 剔除2.2版本(API 8)中有问题的手机,使用UUID替代

import android.content.Context; import android.content.SharedPreferences; import android.provider.Settings.Secure; import android.telephony.TelephonyManager;  import java.io.UnsupportedEncodingException; import java.util.UUID;  public class DeviceUuidFactory {    protected static final String PREFS_FILE = "device_id.xml";   protected static final String PREFS_DEVICE_ID = "device_id";   protected static volatile UUID uuid;    public DeviceUuidFactory(Context context) {     if (uuid == null) {       synchronized (DeviceUuidFactory.class) {         if (uuid == null) {           final SharedPreferences prefs = context               .getSharedPreferences(PREFS_FILE, 0);           final String id = prefs.getString(PREFS_DEVICE_ID, null);           if (id != null) {             // Use the ids previously computed and stored in the             // prefs file             uuid = UUID.fromString(id);           } else {             final String androidId = Secure.getString(               context.getContentResolver(), Secure.ANDROID_ID);             // Use the Android ID unless it's broken, in which case             // fallback on deviceId,             // unless it's not available, then fallback on a random             // number which we store to a prefs file             try {               if (!"9774d56d682e549c".equals(androidId)) {                 uuid = UUID.nameUUIDFromBytes(androidId                     .getBytes("utf8"));               } else {                 final String deviceId = ((TelephonyManager)                      context.getSystemService(                       Context.TELEPHONY_SERVICE)                       .getDeviceId();                 uuid = deviceId != null ? UUID                     .nameUUIDFromBytes(deviceId                         .getBytes("utf8")) : UUID                     .randomUUID();               }             } catch (UnsupportedEncodingException e) {               throw new RuntimeException(e);             }             // Write the value out to the prefs file             prefs.edit()                 .putString(PREFS_DEVICE_ID, uuid.toString())                 .commit();           }         }       }     }   }    /**    * Returns a unique UUID for the current android device. As with all UUIDs,    * this unique ID is "very highly likely" to be unique across all Android    * devices. Much more so than ANDROID_ID is.    *    * The UUID is generated by using ANDROID_ID as the base key if appropriate,    * falling back on TelephonyManager.getDeviceID() if ANDROID_ID is known to    * be incorrect, and finally falling back on a random UUID that's persisted    * to SharedPreferences if getDeviceID() does not return a usable value.    *    * In some rare circumstances, this ID may change. In particular, if the    * device is factory reset a new device ID may be generated. In addition, if    * a user upgrades their phone from certain buggy implementations of Android    * 2.2 to a newer, non-buggy version of Android, the device ID may change.    * Or, if a user uninstalls your app on a device that has neither a proper    * Android ID nor a Device ID, this ID may change on reinstallation.    *    * Note that if the code falls back on using TelephonyManager.getDeviceId(),    * the resulting ID will NOT change after a factory reset. Something to be    * aware of.    *    * Works around a bug in Android 2.2 for many devices when using ANDROID_ID    * directly.    *    * @see http://code.google.com/p/android/issues/detail?id=10603    *    * @return a UUID that may be used to uniquely identify your device for most    *     purposes.    */   public UUID getDeviceUuid() {     return uuid;   } } 

根据版本进行判断的方式:Serial序列号-->UUID (支持数31)

通过Serial 即可,在覆盖率上,你已经成功的获得了98.4%的用户,剩下的1.6%的用户系统是在9 以下的。

通过AndroidID获取,前面已经说过,在8上,有些商家的手机会有一些bug,返回相同的AndroidID,如果Serial和AndroidID都不行

/**  * Return pseudo unique ID  * @return ID  */ public static String getUniquePsuedoID() {   // If all else fails, if the user does have lower than API 9 (lower   // than Gingerbread), has reset their phone or 'Secure.ANDROID_ID'   // returns 'null', then simply the ID returned will be solely based   // off their Android device information. This is where the collisions   // can happen.   // Thanks http://www.pocketmagic.net/?p=1662!   // Try not to use DISPLAY, HOST or ID - these items could change.   // If there are collisions, there will be overlapping data   String m_szDevIDShort = "35" + (Build.BOARD.length() % 10) + (Build.BRAND.length() % 10) + (Build.CPU_ABI.length() % 10) + (Build.DEVICE.length() % 10) + (Build.MANUFACTURER.length() % 10) + (Build.MODEL.length() % 10) + (Build.PRODUCT.length() % 10);    // Thanks to @Roman SL!   // http://stackoverflow.com/a/4789483/950427   // Only devices with API >= 9 have android.os.Build.SERIAL   // http://developer.android.com/reference/android/os/Build.html#SERIAL   // If a user upgrades software or roots their phone, there will be a duplicate entry   String serial = null;   try   {     serial = android.os.Build.class.getField("SERIAL").get(null).toString();      // Go ahead and return the serial for api => 9     return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();   }   catch (Exception e)   {     // String needs to be initialized     serial = "serial"; // some value   }    // Thanks @Joe!   // http://stackoverflow.com/a/2853253/950427   // Finally, combine the values we have found by using the UUID class to create a unique identifier   return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString(); } 

不用READ_PHONE_STATE权限直接获取ROM信息的方式:(支持率较低 16)

String m_szDevIDShort = "35" + //we make this look like a valid IMEI       Build.BOARD.length()%10+ Build.BRAND.length()%10 +       Build.CPU_ABI.length()%10 + Build.DEVICE.length()%10 +       Build.DISPLAY.length()%10 + Build.HOST.length()%10 +       Build.ID.length()%10 + Build.MANUFACTURER.length()%10 +       Build.MODEL.length()%10 + Build.PRODUCT.length()%10 +       Build.TAGS.length()%10 + Build.TYPE.length()%10 +       Build.USER.length()%10 ; //13 digits 

最后贴上自己在项目中用的:

public static String getDeviceId(Context context) {     String deviceId = "";     if (deviceId != null && !"".equals(deviceId)) {      return deviceId;    }     if (deviceId == null || "".equals(deviceId)) {       try {         deviceId = getLocalMac(context).replace(":", "");       } catch (Exception e) {         e.printStackTrace();       }     }     if (deviceId == null || "".equals(deviceId)) {       try {         deviceId = getAndroidId(context);       } catch (Exception e) {         e.printStackTrace();       }     }     if (deviceId == null || "".equals(deviceId)) {              if (deviceId == null || "".equals(deviceId)) {         UUID uuid = UUID.randomUUID();         deviceId = uuid.toString().replace("-", "");         writeDeviceID(deviceId);       }     }     return deviceId;   } 
// IMEI码   private static String getIMIEStatus(Context context) {     TelephonyManager tm = (TelephonyManager) context         .getSystemService(Context.TELEPHONY_SERVICE);     String deviceId = tm.getDeviceId();     return deviceId;   }    // Mac地址   private static String getLocalMac(Context context) {     WifiManager wifi = (WifiManager) context         .getSystemService(Context.WIFI_SERVICE);     WifiInfo info = wifi.getConnectionInfo();     return info.getMacAddress();   }    // Android Id   private static String getAndroidId(Context context) {     String androidId = Settings.Secure.getString(         context.getContentResolver(), Settings.Secure.ANDROID_ID);     return androidId;   }    public static void saveDeviceID(String str) {     try {       FileOutputStream fos = new FileOutputStream(file);       Writer out = new OutputStreamWriter(fos, "UTF-8");       out.write(str);       out.close();     } catch (IOException e) {       e.printStackTrace();     }   }    public static String readDeviceID() {     StringBuffer buffer = new StringBuffer();     try {       FileInputStream fis = new FileInputStream(file);       InputStreamReader isr = new InputStreamReader(fis, "UTF-8");       Reader in = new BufferedReader(isr);       int i;       while ((i = in.read()) > -1) {         buffer.append((char) i);       }       in.close();       return buffer.toString();     } catch (IOException e) {       e.printStackTrace();       return null;     }   } 

对于获取设备唯一ID并没有绝对的方案,这一点在android的官方博客中也提到了,不过以上几种方案,应该可以满足平时的需求,大家可以选择其中自己认为比较好的,用于自己的项目中。

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持VEVB武林网。


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