Android编程实现popupwindow定时消失的方法

// 创建弹出窗口  popupMenu = new PopupWindow(view, sourceView.getWidth() * 2,      LayoutParams.WRAP_CONTENT + 200);  ColorDrawable cd = new ColorDrawable(R.color.white);  popupMenu.setBackgroundDrawable(cd);  popupMenu.update();  popupMenu.setInputMethodMode(PopupWindow.INPUT_METHOD_NEEDED);  popupMenu.setTouchable(true); // 设置popupwindow可点击  popupMenu.setOutsideTouchable(true); // 设置popupwindow外部可点击  popupMenu.setFocusable(true); // 获取焦点  ColorDrawable dw = new ColorDrawable(0x00);  popupMenu.setBackgroundDrawable(dw);  popupMenu.setTouchInterceptor(new View.OnTouchListener() {    @Override    public boolean onTouch(View v, MotionEvent event) {      if (event.getAction() == MotionEvent.ACTION_OUTSIDE) {        popupMenu.dismiss();        return true;      }      timer.start();      return false;    }  });}CountDownTimer timer = new CountDownTimer(3000, 10) {  @Override  public void onTick(long millisUntilFinished) {  }  @Override  public void onFinish() {    popupMenu.dismiss();  }};@Overridepublic PopupWindow createPupupWindow() {  return popupMenu;}@Overridepublic void showPopupMenu() {  if (popupMenu != null && popupMenu.isShowing()) {    popupMenu.dismiss();  } else {    popupMenu.showAsDropDown(sourceView, -sourceView.getWidth() / 2, 0);    timer.start();  }}